mempool name size incorrect?
Andrew Rybchenko
andrew.rybchenko at oktetlabs.ru
Wed Mar 11 10:46:41 CET 2026
On 3/10/26 5:10 PM, Morten Brørup wrote:
> Isn't the RTE_MEMPOOL_NAMESIZE too short?
>
> Looking at the names sizes:
>
> RTE_MEMZONE_NAMESIZE = 32,
> RTE_RING_NAMESIZE = RTE_MEMZONE_NAMESIZE - (sizeof("RG_")=4) + 1 = 29,
> RTE_MEMPOOL_NAMESIZE = RTE_RING_NAMESIZE - (sizeof("MP_")=4) + 1 = 26
>
> Referring to [1], I think it should be fixed as:
> - #define RTE_MEMPOOL_NAMESIZE (RTE_RING_NAMESIZE - \
> sizeof(RTE_MEMPOOL_MZ_PREFIX) + 1)
> + #define RTE_MEMPOOL_NAMESIZE (RTE_MEMZONE_NAMESIZE - \
> sizeof(RTE_MEMPOOL_MZ_PREFIX) + 1)
>
> There is no ring involved, so I guess it is some kind of copy-paste-search-replace error.
>
I guess ring is involved in fact since the default mempool driver is
ring.
See drivers/mempool/ring/rte_mempool_ring.c ring_alloc().
Yes, it is not ideal, but at least it explains why RTE_RING_NAMESIZE
is used.
>
> Looking at the rte_mempool structure [2]:
> struct __rte_cache_aligned rte_mempool {
> char name[RTE_MEMPOOL_NAMESIZE]; /**< Name of mempool. */
> union {
> void *pool_data; /**< Ring or pool to store objects. */
> uint64_t pool_id; /**< External mempool identifier. */
> };
>
>
> Due to the 8-byte alignment of the pool_id field following the name field, fixing the length as suggested doesn't change the memory layout for 64 bit CPU architectures.
> But it does for 32 bit CPU architectures, which will only 4-byte align the pool_id field.
>
> [1]: https://elixir.bootlin.com/dpdk/v26.03-rc1/source/lib/mempool/rte_mempool.h#L128
> [2]: https://elixir.bootlin.com/dpdk/v26.03-rc1/source/lib/mempool/rte_mempool.h#L230
>
>
> Another thing:
> On 32 bit CPU architectures, the cache_size and local_cache fields in the rte_mempool structure are not in the same cache line.
> But I guess we don't really care about 32 bit CPU architectures.
>
>
> Venlig hilsen / Kind regards,
> -Morten Brørup
>
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