[PATCH 1/2] eal: provide macro for GCC builtin constant intrinsic
Andrew Rybchenko
andrew.rybchenko at oktetlabs.ru
Wed May 29 13:42:30 CEST 2024
On 4/1/24 11:34, Morten Brørup wrote:
>> From: Stephen Hemminger [mailto:stephen at networkplumber.org]
>> Sent: Monday, 1 April 2024 00.03
>>
>> On Wed, 20 Mar 2024 14:33:35 -0700
>> Tyler Retzlaff <roretzla at linux.microsoft.com> wrote:
>>
>>> +#ifdef RTE_TOOLCHAIN_MSVC
>>> +#define __rte_constant(e) 0
>>> +#else
>>> +#define __rte_constant(e) __extension__(__builtin_constant_p(e))
>>> +#endif
>>> +
>>
>>
>> I did some looking around and some other project have macros
>> for expressing constant expression vs constant.
>>
>> Implementing this with some form of sizeof math is possible.
>> For example in linux/compiler.h
>>
>> /*
>> * This returns a constant expression while determining if an argument
>> is
>> * a constant expression, most importantly without evaluating the
>> argument.
>> * Glory to Martin Uecker <Martin.Uecker at med.uni-goettingen.de>
>> *
>> * Details:
>> * - sizeof() return an integer constant expression, and does not
>> evaluate
>> * the value of its operand; it only examines the type of its operand.
>> * - The results of comparing two integer constant expressions is also
>> * an integer constant expression.
>> * - The first literal "8" isn't important. It could be any literal
>> value.
>> * - The second literal "8" is to avoid warnings about unaligned
>> pointers;
>> * this could otherwise just be "1".
>> * - (long)(x) is used to avoid warnings about 64-bit types on 32-bit
>> * architectures.
>> * - The C Standard defines "null pointer constant", "(void *)0", as
>> * distinct from other void pointers.
>> * - If (x) is an integer constant expression, then the "* 0l" resolves
>> * it into an integer constant expression of value 0. Since it is cast
>> to
>> * "void *", this makes the second operand a null pointer constant.
>> * - If (x) is not an integer constant expression, then the second
>> operand
>> * resolves to a void pointer (but not a null pointer constant: the
>> value
>> * is not an integer constant 0).
>> * - The conditional operator's third operand, "(int *)8", is an object
>> * pointer (to type "int").
>> * - The behavior (including the return type) of the conditional
>> operator
>> * ("operand1 ? operand2 : operand3") depends on the kind of
>> expressions
>> * given for the second and third operands. This is the central
>> mechanism
>> * of the macro:
>> * - When one operand is a null pointer constant (i.e. when x is an
>> integer
>> * constant expression) and the other is an object pointer (i.e. our
>> * third operand), the conditional operator returns the type of the
>> * object pointer operand (i.e. "int *). Here, within the sizeof(),
>> we
>> * would then get:
>> * sizeof(*((int *)(...)) == sizeof(int) == 4
>> * - When one operand is a void pointer (i.e. when x is not an integer
>> * constant expression) and the other is an object pointer (i.e. our
>> * third operand), the conditional operator returns a "void *" type.
>> * Here, within the sizeof(), we would then get:
>> * sizeof(*((void *)(...)) == sizeof(void) == 1
>> * - The equality comparison to "sizeof(int)" therefore depends on (x):
>> * sizeof(int) == sizeof(int) (x) was a constant expression
>> * sizeof(int) != sizeof(void) (x) was not a constant expression
>> */
>> #define __is_constexpr(x) \
>> (sizeof(int) == sizeof(*(8 ? ((void *)((long)(x) * 0l)) : (int
>> *)8)))
>
> Nice!
> If the author is willing to license it under the BSD license, we can copy it as is.
>
> We might want to add a couple of build time checks to verify that it does what is expected; to catch any changes in compiler behavior.
>
LGTM too, but meanwhile we can continue without it just to unblock build
on MSVC
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