[PATCH 1/6] net/intel: fix Rx vector capability detection

Loftus, Ciara ciara.loftus at intel.com
Tue Oct 14 16:59:07 CEST 2025


> 
> On Tue, Oct 14, 2025 at 08:45:12AM +0000, Ciara Loftus wrote:
> > The common function for detecting whether an rxq could use a vector
> > rx path would automatically disqualify rx queues that had the
> > timestamp offload enabled. This was incorrect behaviour because the
> > iavf driver which uses this common function supports timestamp offload
> > on its vector paths. Fix this by removing the conditional check for
> > timestamp offload.
> >
> > Fixes: 9eb60580d155 ("net/intel: extract common Rx vector criteria")
> > Cc: stable at dpdk.org
> >
> > Signed-off-by: Ciara Loftus <ciara.loftus at intel.com>
> > ---
> >  drivers/net/intel/common/rx.h | 5 ++---
> >  1 file changed, 2 insertions(+), 3 deletions(-)
> >
> > diff --git a/drivers/net/intel/common/rx.h b/drivers/net/intel/common/rx.h
> > index 741808f573..d3e4492ff1 100644
> > --- a/drivers/net/intel/common/rx.h
> > +++ b/drivers/net/intel/common/rx.h
> > @@ -235,9 +235,8 @@ ci_rxq_vec_capable(uint16_t nb_desc, uint16_t
> rx_free_thresh, uint64_t offloads)
> >  			(nb_desc % rx_free_thresh) != 0)
> >  		return false;
> >
> > -	/* no driver supports timestamping or buffer split on vector path */
> > -	if ((offloads & RTE_ETH_RX_OFFLOAD_TIMESTAMP) ||
> > -			(offloads & RTE_ETH_RX_OFFLOAD_BUFFER_SPLIT))
> > +	/* no driver supports buffer split on vector path */
> > +	if (offloads & RTE_ETH_RX_OFFLOAD_BUFFER_SPLIT)
> >  		return false;
> >
> >  	return true;
> 
> Given that we check all offload flags later when doing final path
> selection, can we drop the flags check here completely? Just have this
> funciont check on the non-feature-related conditions, such as ring size
> etc.

Sure.
This function is used by ixgbe which doesn't use the common
rx path select function yet. But I think this check is
redundant for ixgbe because it's not supported on any of its
paths so initialisation would fail earlier than here, during
dev_configure.

> 
> /Bruce


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